Question

The molecular weight of two gases a and b are 16 and 64 respectively. Gas a
And what will be the ratio of diffusion motions of b?​

Answer 1

The ratio of diffusion of gas-a to gas-b is 2:1

Explanation:

Graham's law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

$\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}$

Diffusion rate of gas-a = R

Molar mass of gas-a=M= 16 g/mol

Diffusion rate of gas-b = R'

Molar mass of gas-b=M'= 64 g/mol

$\frac{R}{R'}=\sqrt{\frac{M'}{M}}$

$\frac{R}{R'}=\sqrt{\frac{64 g/mol}{16 g/mol}}=\frac{8}{4}=2$

The ratio of diffusion of gas-a to gas-b is 2:1.

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