Question

The molecule in which central atom has 50% S-character in its hybridisation is
O BeCl2
О ВСІЗ
O NH3
O CH4​

Answer 1

The molecule in which central atom has 50 % S - character in its hybridisation is ...

1. BeCl₂
2. BCl₃
3. NH₃
4. CH₄

solution : if the central atoms has 50% S - character then hybridisation must be “sp” .

directly, question ask us to find out the molecule in which hybridisation of central atom is Sp.

let's check all options.

hybridisation of BeCl₂ :

valence electrons = (2 + 2 × 7) = 16

bond pair = 2

so lone pair = (16 - 2 × 8)/2 = 0

Therefore hybridisation of BeCl₂ is sp.

similarly hybridisation of BCl₃ :

bond pair = 3

lone pair = (3 + 3 × 7 - 3 × 8)/2 = 0

so hybridisation is sp²

hybridisation of NH₃ :

bond pair = 3

lone pair = (5 + 3 × 1 - 2 × 3)/2 = 1

so hybridisation is sp³

hybridisation of CH₄ : sp³ [ you know it already]

here it is clear that hybridisation of BeCl₂ is sp , so BeCl₂ is the molecule in which central atom has 50% s - character in its hybridisation.

Answer 2

Answer:

b

Explanation:

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