Question

the molecule of mass m ,moving with velocity v are absorbed after colliding with the walls of container if the number of molecule per unit volume of gas is N ,then the pressure exerted by the gas will be ? a) mNV^2÷2 b) 2mNv2 c)mNv^2÷3 d) mNv^2​

Answer 1

answer : option (d) mNv²

explanation : mass of a gaseous molecule = m

number of molecule per unit volume = N

Let volume of container = V

then, number of molecules in container = NV

and momentum of each molecule = mv

so, momentum of total molecule = (NV)mv

we know, pressure = force/Area

= (momentum/time )/Area

= {(NV)mv/t}A

= (NAl)mv/At [ volume, V = Al ]

= Nmv × (l/t)

= Nmv² [ as we know, velocity= displacement/time ]

hence, option (d) is correct choice.

Answer 2

Answer:

d) 2mNv^2

pressure=Force/Area

               =(Momentum/Time)/Area

               =Nmv^2