The molecules of a given mass of a gas have r.m.s velocity of 200ms−1 at 27oC and 1.0×105Nm−2 pressure. When the temperature and pressure of the gas are respectively, 127oC and 0.05×105Nm−2, the r.m.s. velocity of its molecules in ms−1 is :
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Vrms directly proportional to √T
so, V2/V1 = √T2/√T1
V2/200 =√400/√300 (by cancelling zero)
V2 = 2×200/√3
V2 = 400/√3
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