Question

The moles of O2 required for reacting with 6.8g ammonia (4NH3 +5O2➡️ 4NO +6H2O)?

Answer 1

in order to find no. of moles of HOW divide the stoichiometric coefficient of HOW from NH3 and multiply it by no. of moles of NH3

Answer 2

Answer:

Mass of ammonia = 6.8 g

Molar mass of ammonia = 17.031 g/mole

First we have to calculate the moles of ammonia.

Now we have to calculate the moles of  required.

The balanced chemical reaction is,

From the reaction, we conclude that

4 moles of  react with 5 moles of

0.399 moles of  react with  of

Therefore, the moles of  required is 0.5 moles.

Explanation: