Question

The moment of 30 N force passing through the coordinates (4,0) and (0,3)origin is __N.m.​

Answer 1

Answer:

The moment of 30 N force passing through the coordinates (4,0) and (0,3)origin is 72 N.m

Explanation:

Answer 2

Answer:

The moment of the force is 150Nm.

Explanation:

The moment of the force is called torque. Which is given as,

$\tau=F\times d$             (1)

Where,

τ=moment of force

F=force

d=point at which the moment is to be found

From the question we have,

F=30N

$\vec r_1=4\hat{i}$   (2)

$\vec r_2=3\hat{j}$   (3)

$d=\vec r_2-\vec r_1$  (4)

By substituting equations (2) and (3) we get;

$d=3\hat{j}-4\hat{i}$

The magnitude of d will be given as,

$d=\sqrt{3^2+4^2} =\sqrt{25} =5m$

By substituting the value of F and d in equation (1) we get;

$\tau=30\times 5=150Nm$

Hence, the moment of the force passing through the coordinates is 150Nm.