Question

The moment of a force of 12 N about a pivot is 4.8 Nm, what is the perpendicular distance of the point of force application from the pivot?​

Answer 1

Answer:

Given that moment of force is 5 N-m about a point O when we apply a force of 10 N. We know that moment of force is given by formula rXF.

5=r×10

r=0.5m.

Hence we apply a force at a perpendicular distance of 0.5 m.

Explanation:

folllow me n thank my answer