Question

the moment of a force of 15 N acting at a normal distance X from a distance of rotation is 6.0 m. what is the value of X?​

Answer 1

Your Answer :-

Moment Of Force :- The Turning effect of a force acting on a body about the axis passing through a fixed point is called Moment Of Force .

The moment of force is equal to product of the magnitude of the force and the perpendicular distance of the line of action of the force from the axis of rotation

Coming Back to the Question .

tau = Force * Perpendicular distance .

= 20 N * 0.5 m

= 10 N.m

Hence Moment of Force is \boxed{10N.m}

10N.m

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^_^ ^_^

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Answer 2

Concept:

• moment of force
• Torque is the rotational equivalent of force in physics and mechanics. It is also known as the rotating force, turning effect, moment, and moment of force.
• It illustrates how a force can cause a change in the body's rotational motion.
• The absence of an equal and opposing force directly along a force's path of action causes a moment.

Given:

• Moment of force = 6 Nm
• Force F = 15 N

Find:

• The normal distance between the point at the force is applied and the point of rotation. X

Solution:

Moment of force = F X

6 Nm = 15 N *X

X = 6/15

X = 2/5

X = 0.4 m

The value of X is 0.4 m.

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