Question

the moment of a force of 25 N about a point is 2.5 Nm. Find the perpendicular distance of force from that point​

Answer 1

Answer:

here refer the attachment

Explanation:

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Answer 2

Given :-

• Momentum of a force of 25 N about a point of 2.5 cm.

Unknown :

• Perpendicular distance of force from that point.

● Solution :-

• $\boxed{distance = \dfrac{momentum}{force} }$

we are now putting values;

$\rightarrow \: \dfrac{2.5}{25}$

$\rightarrow \: \dfrac{1}{10} = 0.1 \: cm$

So our final answer is 10 cm

$\longrightarrow \bf \: 10 \: cm. \: . \: .. \: .. \:$