Question

The moment of a force of 25N about a point is 2.5Nm. Find the perpendicular distance of force from that point.

A. 1 cm
B. 10 cm
C. 1 m

Answer 1

Answer:

Force applied = 25 N  

⊥ distance from the point of rotation = ?  

Moment of force = Force × ⊥ distance  

2.5 = 25 × ⊥ distance  

distance = 2.5/25 = 1/10 m = 10 cm

(B) 10cm

Answer 2

Answer:

Moment of force =Force × perpendicular distance

perpendicular distance =moment of Force /Force

perpendicular distance = 2.5/25

perpendicular distance =0.1m

perpendicular distance =10cm