The moment of a force of 25N about a point is 7.5 Nm. What is the perpendicular
distance of the force from that point.
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Force applied = 25 N
\bot⊥ distance from the point of rotation = ?
Moment of force = Force \times× \bot⊥ distance
2.5 = 25 \times× \bot⊥ distance
distance = 2.5/25 = 1/10 m = 10 cm
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