Question

The moment of a force of 25N about a point is 7.5 Nm. What is the perpendicular
distance of the force from that point.​

Answer 1

Answer:

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Answer 2

Force applied = 25 N

\bot⊥ distance from the point of rotation = ?

Moment of force = Force \times× \bot⊥ distance

2.5 = 25 \times× \bot⊥ distance

distance = 2.5/25 = 1/10 m = 10 cm

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