Physics, asked by kimruanlimosha, 1 month ago

The moment of a force of 25N about a point is 7.5 Nm. What is the perpendicular distance of the force from that point.

Answers

Answered by niladrisaha07

0

Answer:

I don't understand the question

Answered by ItzzTejasvi

1

Explanation:

Solution:

Force applied = 25 N

⊥ distance from the point of rotation = ?

Moment of force = Force \times× ⊥ distance

2.5 = 25 times× ⊥ distance

distance = 2.5/25 = 1/10 m = 10 cm

hope it will help you

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