Question

The moment of a force of 5 N about a point P is
2 N m. Calculate the distance of point of application
of the force from the point P.​

Answer 1

Force (F)= 5N

Movement of force (T)=2Nm

Let the distance of point of application of force from point P be d.

T=Fd

2=5×d

d= 2/5

d= 0.4 metre.

Hence , the required answer is 0.4 metre.

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