Question

The moment of a magnet (15 cm × 2 cm × 1 cm) is 1.2 A-m².
What is its intensity of magnetisation?
(a) 4 × 10⁴ A m⁻¹ (b) 2 × 10⁴ A m⁻¹
(c) 10⁴ A m⁻¹ (d) None of these

Answer 1

Intensity of Magnetisation

$i = \frac{m}{v} \\ \\ = \frac{1.2}{(15 \times 2 \times 1) {10}^{ - 6} } \\ \\ = 4 \times {10}^{4} {am}^{ - 1}$

Answer 2

Answer:

c option is correct between them

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