Physics, asked by gpkanjana, 6 days ago

The moment of force 18 N about a pivot is 9 N.m. Calculate the distance of force from the pivot.​

Answers

Answered by manasaaaa2008
1

Answer:

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Answered by suhanishrirame
2

Answer:

Given that moment of force is 5 N-m about a point O when we apply a force of 10 N. We know that moment of force is given by formula rXF.

Given that moment of force is 5 N-m about a point O when we apply a force of 10 N. We know that moment of force is given by formula rXF.5=r×10

Given that moment of force is 5 N-m about a point O when we apply a force of 10 N. We know that moment of force is given by formula rXF.5=r×10r=0.5m.

Given that moment of force is 5 N-m about a point O when we apply a force of 10 N. We know that moment of force is given by formula rXF.5=r×10r=0.5m.Hence we apply a force at a perpendicular distance of 0.5 m.

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