Question

The moment of force 18 N about a pivot is 9 N.m. Calculate the distance of force from the pivot. ​

Answer 1

Explanation:

Given that moment of force is 5 N-m about a point O when we apply a force of 10 N. We know that moment of force is given by formula rXF.

5=r×10

r=0.5m.

Hence we apply a force at a perpendicular distance of 0.5 m.

Answer 2

Answer:

Solution:

Force applied = 25 N

\bot distance from the point of rotation = ?

Moment of force = Force \times \bot distance

2.5 = 25 \times \bot distance

distance = 2.5/25 = 1/10 m = 10 cm