Question

The moment of force about a point P is 30Nm If perpendicular distance from the pointis 10m. Find the applied force.​

Answer 1

Answer:

3N

Explanation:

Moment of force=30Nm

Perpendicular distance=10m

Force applied =?

Moment of force=Force applied×Perpendicular distance

30=Force applied ×10

Force applied=3N

Answer 2

Answer:

F=3N

Explanation:

M=rFsin theta

where M is the moment of force and r is the distance F is the applied force

then,

30=10F sin(90°) since perpendicular

F=30/10. (since sin 90°=1)

F=3N