Question

The moment of force of 10 N about a fixed point O is 5 N m. Calculate the distance of the point O from the line of action of the force.

5. A uniform half meter rule can be balanced at the 29 cm mark when a mass of 20 g is hung from its one end.
a. Draw a diagram for the arrangement
b. Find the mass of the half meter rule
plz give the correct answer

Answer 1

Answer:

Let the weight of the half metre rule be x gf and it acts at the 25 cm mark (centre of gravity).

Now,

Acticlockwise moment = x×4

Clockwise moment = 20×21

In equilibrium,

Anticlockwise moment = Clockwise moment

4x=20×21

x=105 gf.

Thus, the weight of the metre rule is 105gf.

We know, one gf is the force acting on the body of mass 1 grams, thus mass of the body is 105grams.

solution

Explanation:

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