The moment of force of 10 N about a pivot is 5Nm calculate the distance of force from the pivot is
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Given that moment of force is 5 N-m about a point O when we apply a force of 10 N. We know that moment of force is given by formula rXF.
5=r×10
r=0.5m.
Hence we apply a force at a perpendicular distance of 0.5 m.
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