Question

The moment of force of 10N about a pivot is 5Nm.The distance of force from the pivot is?​

Answer 1

Moment of force =10 m

Fixed point is at 5 N m

we know,

distance =moment/force

=5 N m/10 N

= 1/2 m

= 0.5m

Answer 2

Answer: 0.5 m

Explanation:

• We know that the moment of force is defined as the product of the force and the perpendicular distance.
• Given the moment of force=5Nm

                  Force=10N

• Moment of force=F×d

      ⇒ 5=10×d

      ⇒ d=$\frac{5}{10}$

      ∴ d=0.5m

• Hence, the distance is 0.5 m.

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