The moment of force of 20 N about point P is 100 Nm calculate the distance of point of application of force of that point
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Answer:
Given : F=5 N
Moment of force (or torque ) τ=20 Nm
Let the distance of point of application of force from point P be d.
∴ τ=Fd
OR 20=5×d ⟹d=4 m
Explanation:
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