Question

the moment of force of 20n about an axis of rotation at a distance o.5 from the force is

Answer 1

Answer:

(1) Moment of force means torque.

τ=force×⊥distance

τ=20×0.5

τ=10N−m

(2) τ=force×distance

τ=5×  

100

10

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τ=0.5N−m........please vote...

Explanation:

Answer 2

Question-

Find the moment of force of 20N about axis of rotation at distance 0.5m from the force.

Given-

• Force = 20N
• ⊥ Distance = 0.5m

To find-

• Moment of force

Calculation-

We know,

${\underline {\underline {\boxed {\red {\sf {Moment \: of \: force = Force \times ⊥ Distance }}}}}}$

$\sf {☞ \: Moment \:of \:force = F × ⊥ Distance}$

$\sf {☞ \: Moment \: of\: force = 20N × 0.5 m}$

$\sf { ☞ \:Moment \: of \:force = 10 Nm }$

Therefore, the moment of force of 20N about axis of rotation at distance 0.5m from the force is 10Nm.

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