Question

The moment of force of 50 N about a point is 5 Nm. Find the perpendicular distance of force from that point​

Answer 1

Answer:

Given that moment of force is 5 N-m about a point O when we apply a force of 10 N. We know that moment of force is given by formula rXF.

5=r×10

r=0.5m.

Hence we apply a force at a perpendicular distance of 0.5 m.

Explanation:

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Answer 2

Answer:

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Explanation:

The moment of force =5Nm

Force applied= 50

distance of force from the point​ of rotation ?

moment of force $*$ distance

5=50*x

x= distance = 5/50 = 1/10 Nm

=1/10*100

10cm