Question

The moment of force of 5N force on a body at a distance 20 cm from a pivot point is



1000 N m

1 N m

100 N m

10 N m

​

Answer 1

Answer:

The answer is 100 Nm.

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Answer 2

Answer:

Solution: Given Force F = 5 N,

Distance D = 20 cm = 0.2 m

Thus,The moment of force = force F × distance D

= 5 N × 0.2 m

=1 N m

Explanation:

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