Physics, asked by abhiraj8112, 1 year ago

The moment of inertia and rotational kinetic energy of a flywheel are 20 kgm2 and 100 j

Answers

Answered by ranjaydas

Rotational Kinetic Energy

Any moving object has kinetic energy. We know how to calculate this for a body undergoing translational motion, but how about for a rigid body undergoing rotation? This might seem complicated because each point on the rigid body has a different velocity. However, we can make use of angular velocity—which is the same for the entire rigid body—to express the kinetic energy for a rotating object. (Figure) shows an example of a very energetic rotating body: an electric grindstone propelled by a motor. Sparks are flying, and noise and vibration are generated as the grindstone does its work. This system has considerable energy, some of it in the form of heat, light, sound, and vibration. However, most of this energy is in the form of rotational kinetic energy. Energy in rotational motion is not a new form of energy; rather, it is the energy associated with rotational motion, the same as kinetic energy in translational motion. However, because kinetic energy is given by , and velocity is a quantity that is different for every point on a rotating body about an axis, it makes sense to find a way to write kinetic energy in terms of the variable ω , which is the same for all points on a rigid rotating body. For a single particle rotating around a fixed axis, this is straightforward to calculate. We can relate the angular velocity to the magnitude of the translational velocity using the relation vt = ω r , where r is the distance of the particle from the axis of rotation and v t is its tangential speed. Substituting into the equation for kinetic energy, we find K = 1 2 m v t = 1 2 m ( ω r ) 2 = 1 2 ( m r 2 ω 2.

In the case of a rigid rotating body, we can divide up any body into a large number of smaller masses, each with a mass m j and distance to the axis of rotation r j , such that the total mass of the body is equal to the sum of the individual masses: M = ∑ j m j . Each smaller mass has tangential speed v j , where we have dropped the subscript t for the moment. The total kinetic energy of the rigid rotating body is K = ∑ j 1 2 m j v 2 2 m and since ω j = for all masses, K = 2 ( ∑ The units of (Figure) are joules (J). The equation in this form is complete, but awkward; we need to find a way to generalize it.

Moment of Inertia If we compare (Figure) to the way we wrote kinetic energy in Work and Kinetic Energy, or now, we leave the expression in summation form, representing the moment of inertia of a system of point particles rotating about a fixed axis. We note that the moment of inertia of a single point particle about a fixed axis is simply with r being the distance from the point particle to the axis of rotation. In the next section, we explore the integral form of this equation, which can be used to calculate the moment of inertia of some regular-shaped rigid bodies. The moment of inertia is the quantitative measure of rotational inertia, just as in translational motion, and mass is the quantitative measure of linear inertia—that is, the more massive an object is, the more inertia it has, and the greater is its resistance to change in linear velocity. Similarly, the greater the moment of inertia of a rigid body or system of particles, the greater is its resistance to change in angular velocity about a fixed axis of rotation. It is interesting to see how the moment of inertia varies with r, the distance to the axis of rotation of the mass particles in (Figure). Rigid bodies and systems of particles with more mass concentrated at a greater distance from the axis of rotation have greater moments of inertia than bodies and systems of the same mass, but concentrated near the axis of rotation. In this way, we can see that a hollow cylinder has more rotational inertia than a solid cylinder of the same mass when rotating about an axis through the center. Substituting (Figure) into (Figure), the expression for the kinetic energy of a rotating rigid body becomes We see from this equation that the kinetic energy of a rotating rigid body is directly proportional to the moment of inertia and the square of the angular velocity. This is exploited in flywheel energy-storage devices, which are designed to store large amounts of rotational kinetic energy. Many carmakers are now testing flywheel energy storage devices in their automobiles, such as the flywheel, or kinetic energy recovery system, shown in (Figure). Figure is a photo of a kinetic energy recovery system flywheel installed next to the driver’s seat in a car. The rotational and translational quantities for kinetic energy and inertia are summarized in (Figure). The relationship column is not included because a constant doesn’t exist by which we could multiply the rotational quantity to get the translational quantity, as can be done for the variables in (Figure).

Answered by CarliReifsteck