Question

the moment of inertia of a 500gm cylinder of radius 10cm about its natural axis is

Answer 1

m = 500gm = 0.5kg
r = 10cm = 0.1m

$i \: = \binom{m {r}^{2} }{2}$
i = 0.01/ 4
i = 0.0025 kg-m^2

P.S.- Assuming that by cylinder you mean solid cylinder.

Hope this helps.

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Answer 2

Answer:

12500 g. cm²

Explanation:

Assuming, natural axis is the diameter of the disc

Moment of inertia about the natural axis is given by :- 1/4 x m X R²

Moment of inertia about the natural axis is given by :- 1/4 x 500 x 10²

Moment of inertia about the natural axis is given by :- 12500 g. cm²