The moment of inertia of a body about a given axis is 1.2 kg m². Initially, the body is at rest . In order to produce a rotational kinetic energy of 1500 J, an angular acceleration of 25 rad s⁻² must be applied about that axis for a duration of(a) 4 s(b) 2 s(c) 8 s(d) 10 s
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Answer:
B) 2 seconds
Explanation:
Inertia of the body = 1.2 kg m² (Given)
Angular acceleration = 25 rad s⁻² (Given)
E = 1/2ω²
= 1500 = 1/2×1.2ω²
= ω² = 3000/1.2
= ω² = 2500
= ω = 50 rads⁻1
t = ω/α ( because ω = 0+at)
t = 50/25
t = 2
Therefore, the duration for the axis should be 2 seconds
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