Question

the moment of inertia of a circular ring about diameter is 4.0gm-cm². find the moment of inertia about an axis through center and perpendicular to its plane​

Answer 1

Answer:

which subject of your question

Answer 2

Moment of Inertia of ring about an axis perpendicular to its plane is I=MR

2

By perpendicular axis theorem , moment of Inertia about any diameter I

′

=

2

I

=

2

MR

2

Moment of Inertia about any tangent is

I

1

=I

′

+MR

2

=

2

MR

2

+MR

2

=

2

3MR

2

=

2