Question

The moment of inertia of a circular ring about the axis passing through its centre and perpendicular to the plane is 200gcm2 the radius of the wing is 5 cm find the mass of the radius

Answer 1

Answer:

I=Mr2 so m=i/r2. m=8gm

Answer 2

Answer:

Mass of the ring is 8 g.

Explanation:

The explanation is in the above attachment .