Question

The moment of inertia of a circular ring of 1 Kg about an axis passing through its center and perpendicular to its plane is 4 Kg-m^2. The diameter of the ring is *

A) 2 m

B) 4 m

C) 5 m

D) 6 m​

Answer 1

Answer:

. . . . . . 4m

Step by Step:

Moment of inertia of circular ring about an axis passing through its center of mass and perpendicular to its plane

here

m=1 kg

=

Therefore, diameter of ring = 4 m.