The moment of inertia of a flat annular ring having
mass M, inner radius a and outer radius b about
the diametric axis through the centre is
M
(1)-(b-a)
4
(2) M (52-6?)
M
(3) M (52 + a')
2
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Answered by
0
Answer:
moment of inertia of a ring through the diametric axis is MR^2/2
so the answer will be M(b^2 - a^2)/2
Answered by
1
Answer:
The answer is option: (3) M/4 (b^2 + a^2)
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