Question

The moment of inertia of a flywheel making 300 revolutions per minute is 0.3 kgm² find the Torque required to bring it to rest in 20s

Answer 1

Answer:

We know, Torque = moment of inertia × angular acceleration. so, torque = 0.3 × -π/2 = -0.15π Nm. hence, magnitude of torque is 0.15π Nm.

Explanation: