the moment of inertia of a hollow thick spherical shell of mass M and its inner radius R1 and outer radius R2about its diameter is
Answers
Answered by
1
Rho = M/ 4/3π(R2 cbe - R1 cubr)
I shell = 2/5M2R2square -2/5M1R1square
M2 = rho * 4/3πR2 cube
M1 = MR1CUBE/R2CUBE -R1CUBE
PUTTING VALUES
I = 2M(R2^5 -R1^5) / 5(R2 cube -R1cube)
Answered by
9
---------------
I =2/5 MR^2
-----------------
I =2/5 MR^2
-----------------
Similar questions
Math,
7 months ago
Math,
7 months ago
Math,
1 year ago
Social Sciences,
1 year ago
Physics,
1 year ago