the moment of inertia of a hollow thick spherical shell of mass M and its inner radius R1 and outer radius R2about its diameter is
Answers
Answered by
11
Rho = M/ 4/3π(R2 cbe - R1 cubr)
I shell = 2/5M2R2square -2/5M1R1square
M2 = rho * 4/3πR2 cube
M1 = MR1CUBE/R2CUBE -R1CUBE
PUTTING VALUES
I = 2M(R2^5 -R1^5) / 5(R2 cube -R1cube)
I shell = 2/5M2R2square -2/5M1R1square
M2 = rho * 4/3πR2 cube
M1 = MR1CUBE/R2CUBE -R1CUBE
PUTTING VALUES
I = 2M(R2^5 -R1^5) / 5(R2 cube -R1cube)
Answered by
3
Rho = M/ 4/3π(R2 cbe - R1 cubr)
I shell = 2/5M2R2square -2/5M1R1square
M2 = rho * 4/3πR2 cube
M1 = MR1CUBE/R2CUBE -R1CUBE
PUTTING VALUES
I = 2M(R2^5 -R1^5) / 5(R2 cube -R1cube)
I shell = 2/5M2R2square -2/5M1R1square
M2 = rho * 4/3πR2 cube
M1 = MR1CUBE/R2CUBE -R1CUBE
PUTTING VALUES
I = 2M(R2^5 -R1^5) / 5(R2 cube -R1cube)
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