Physics, asked by siwachprachi70, 11 hours ago

the moment of inertia of a hollow thin shell of mass m and radius r about its geometrical axis is​

Answers

Answered by vivek110995
1

Answer:

As it is hollow, so almost all the mass is at periphery. Hence total moment of inertia aboit geometrical axis will be -

m {r}^{2}

Where, m is tge total mass and r is radius

Attachments:
Answered by rahul123437
0

The moment of inertia of a hollow thin shell of mass m and radius r about its geometrical axis is 2/3 Mr^2

Explanation:

  • Moment of inertia dictates that when a mass strikes an equal mass at rest and sticks to it, the combination must move at half the velocity, because the product of mass and velocity must remain constant.

Consider a hollow sphere of radius r.

Consider a strip(ring shape) on this surface of angular width dθ.

The strip being at position  from horizon.

Mass of elemental strip dm= m/4\pi r^2×2\pi rcos×rd0

i = 2/3Mr^2

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