Question

The moment of inertia of a meter scake of mass 0.6kg about an axis perpendicular to the scale and located at the 20 cm position on the scale in kg m^2 is?(breadth of the scale is negligible)
a. 0.074
b.0.104
c.0.148
d.0.208

Answer 1

Answer ⇒ Option (a).  0.074

Explanation ⇒ Using the Parallel Axis Theorem,

the Moment of Inertia about an axis at an distance of 20 cm from its centre is given as,

  I = ML²/12 + Ma²

Now,

Using the conditions, given in Questions,

  M = 0.6 kg, L = 1 m.

a = 20/100 m = 0.2 m.

Substituting these values in the Formula, we will get,

I = 0.6 (1²/12 + 0.2²)

∴ I = 0.6(1/12 + 4/100)

∴ I = 0.6(0.0833 + 0.04)

∴ I = 0.6 × 0.123

∴ I = 0.074 kg-m².

Hence, Option (a). is the correct choice.

Hope it helps.

Answer 2

Answer:

Explanation

:

  I = ML²/12 + Ma²

Now,

Using the conditions, given in Questions,

  M = 0.6 kg, L = 1 m.

a = 20/100 m = 0.2 m.

Substituting these values in the Formula, we will get,

I = 0.6 (1²/12 + 0.2²)

∴ I = 0.6(1/12 + 4/100)

∴ I = 0.6(0.0833 + 0.04)

∴ I = 0.6 × 0.123

∴ I = 0.074 kg-m².