Question

the moment of inertia of a ring of mass m and radius r about pq axis​

Answer 1

Answer:

By using perpendicular axis theorem,

{I_{zz}} = {I_{xx}} + {I_{yy}}I

zz=I xx +I yy

about diameter so {I_{xx}} = {I_{yy}}I xx =I yy

so {I_{zz}} = 2 {I{xx}}I

zz=2Ixx

so moment of inertia about diameter {I_{xx}} = \dfrac {I_{zz}}{2}I

xx = 2I zz

so let moment of inertia about z axis be I

in that case answer will be I/2.