the moment of inertia of a rod of length 1m and mass m about the axis which is 1/3 m from one end is equal to
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Here we can use parallel axis theorem.
as you know that moment of inertia of a rod about centre of mass is ML²/12
then from centre of mass to one end distance =L/2
then, moment of inertia at any end of rod=[ML²/12]+[M(L/2)²]
=(ML²/12)+(ML²/4)
=4ML²/12 = ML²/3
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