Physics, asked by anisha4591, 11 months ago

The moment of inertia of a rod of length l(small l) about an axis passing through its centre of mass and
perpendicular to rod is 'I'(capital i).The moment of inertia of hexagonal shape formed by six such rods, about
an axis passing through its centre of mass and perpendicular to its plane will be​

Answers

Answered by heyj3
1

Answer:

●7Ml^2/48 is the answer.

Explanation:

●I=Icm+M(l4)2I=Icm+M(l4)2

●Ml212+Ml216=Ml212+Ml216

●4Ml2+3Ml248=4Ml2+3Ml248

●7ml^2/48

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