Question

The moment of inertia of a solid cylinderabout its geometricak axis is

Answer 1

L2 = 3R2

as MI of a solid cylinder about its own axis is ½ MR2

and MI about an axis passing through its centre of gravity and perpendicular to its length is

M(L2/12 + R2/4)

 ½ MR2 = M(L2/12 + R2/4)

R2/2 = L2/12 + R2/4

R2/2 – R2/4 = L2/12

L2 = 3R2

L1/2 = 31/2 R

Answer 2

The moment of inertia of a solid cylinderabout its geometricak axis is =mr²/2