The moment of inertia of a solid sphere about an axis passing through its centre is 0.8kgm^2. The moment of inertia of another solid sphere whose mass is same as mass of first sphere, but the density is 8 times density of first sphere, about an axis passing through its centre is
Answers
Given :
The moment of inertia of solid sphere = 0.8 kgm²
Density of first sphere = ρ
Density of another sphere = 8ρ
To Find :
The moment of inertia of another sphere
Solution :
- Moment of inertia ∝ Radius²
I ∝ R²
I₁/I₂ = R₁²/R₂²
- The density of a body ∝ 1/Radius³
ρ ∝ 1 /R³
ρ₁/ρ₂ = R₂³/R₁³
R₁/R₂ = (ρ₂/ρ₁)^(1/3)
- By substituting in above relation we get
I₁/I₂ = (ρ₂/ρ₁))^(2/3)
I₁/I₂ = 4
I₂ = I₁/4
I₂ = 0.2kgm²
The moment of inertia of second sphere is 0.2kgm²
Answer: The correct answer is 0.2
Explanation:
Let the radius of first sphere be and radius of second sphere be .
Given in the question,
= 0.8 (Moment of Inertia about an axis passing through its centre)
mass of both sphere are same = m
For a solid sphere we know that density ρ α
Let ρ1 be the density of first sphere and ρ2 be the density of second sphere.
∴ ρ2 = 8ρ1
∴ ρ1 / ρ2 = () ................. equation 1
= ? (Moment of Inertia about an axis passing through its centre)
∴Moment of Inertia of a sphere = = X
Since, the mass is same, we can rewrite above as,
α ( Directly proportional)
∴ = () ................. equqation 2
From equations 1 and 2 we can write,
= (ρ2 / ρ1)
but ρ2 = 8ρ1
∴ = (8ρ1 / ρ1)
∴ = (8)
and = 0.8 (GIven in the question)
=
= 0.2
∴ Moment of Inertia of second sphere about an axis passing through its centre is 0.2 .