Question

The moment of inertia of a solid sphere about an axis
2
passing through centre of mass is MR^2, then its
5
radius of gyration about a parallel axis at a distance
2R from first axis is​

Answer 1

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Explanation:

Answer 2

$\huge \star \mathfrak\red{ᴀɴsᴡᴇʀ}$

By, Parallel axis theorm

I at 2R is 2MR

2

/5+M(2R)

2

=22MR

2

/5

Radius of gyration, Mk

2

=22MR

2

/5⇒k=

22/5

×R.