The moment of inertia of a thin rod of mass M and length L about an axis passing through its centre and normal to its length is given by ML2 /12. Using theorem of parallel axes, find its moment of inertia about an axis passing through on end and normal to its length, if L = 1m and M = 0.2 Kg
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the moment of inertia =ml2/3 when put these value we got that value
the moment of inertia =ml2/3 when put these value we got that value
Anonymous:
good question
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