Question

The moment of inertia of a thin rod of mass M and length L about an axis passing through its
centre and normal to its length is given by ML
2
/12. Using theorem of parallel axes, find
its moment of inertia about an axis passing through on end and normal to its length, if L = 1m
and M = 0.2 Kg.

Answer 1

You can calculate it by the formula i.E ML^2/3

Answer 2

I AB = I KL + Mh^2

I =(0.2 x 0.1 x 0.1 ) / 12 + ( 0.2 x 0.1 x 0.1 )/4

I= (0.2 x 0.1 x 0.1 ) / 3

I = (2/3 ) x 10^-3 kg m^2