the moment of inertia of a thin uniform rod of mass m and length l about an axis passing through its centre and normal to its length is gives by ML/12 ussing theorem of parallal axes find its moment o inertia about an axis passing through on end and normal to its length if L=1m and M=0.2 kg
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Moment of inertia passing through its centre and normal to its length = I = ML^2/12
Now ,by using parallel axis theorem,
Moment of inertia about an axis passing through one end and normal to its length = I' = ML^2/12 + M(L/2)^2
= ML^2/12 + ML^2/4
= ML^2/3
= (0.2)(1)^2/3
= 0.06 Kg-m^2
Now ,by using parallel axis theorem,
Moment of inertia about an axis passing through one end and normal to its length = I' = ML^2/12 + M(L/2)^2
= ML^2/12 + ML^2/4
= ML^2/3
= (0.2)(1)^2/3
= 0.06 Kg-m^2
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