The moment of inertia of a triangular lamina of mass M and height h about its centre of mass is..
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Mass per unit area= M 1/2 ah
base= a
Moment of inerta= I = 1/2 x M/1/2ah x 1/2ax x xdx
x is the small strip along h from base
So, moment of inertia at base = 1/2 x M/h limit x².dx
= M/2h (x³/ 3)
= M/2h . h³/3
= Mh²/6
base= a
Moment of inerta= I = 1/2 x M/1/2ah x 1/2ax x xdx
x is the small strip along h from base
So, moment of inertia at base = 1/2 x M/h limit x².dx
= M/2h (x³/ 3)
= M/2h . h³/3
= Mh²/6
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