Question

The moment of inertia of a uniform circular disc about a tangent in its own plane is 5/4MR^2 , where M is mass and R is radius of the disc. Find its moment of inertia about an axis through its centre and perpendicular to its plane.

Answer 1

moment of inertia of disc at tangent=5/4mr²=I +mr² (by parallel axis theorem)
I=5/4mr²-mr²=1/4mr²
by perpendicular axis theorem
I+I=I°(perpendicular to plane)
1/4mr²+1/4mr²=mr²/2

Answer 2

moment of inertia of disc at tangent=5/4mr²=I +mr² (by parallel axis theorem)

I=5/4mr²-mr²=1/4mr²

by perpendicular axis theorem

I+I=I°(perpendicular to plane)

1/4mr²+1/4mr²=mr²/2

Plz mark this answer as brainlist