Physics, asked by Pratham5906, 1 year ago

The moment of inertia of a uniform circular disc of radius ‘R’ and mass ‘M’ about an axis passing from the edge of the disc and normal to the disc is(a) MR²(b) \frac{1}{2}MR²(c) \frac{3}{2}MR²(d) \frac{7}{2}MR²

Answers

Answered by atulrajcool
2
c is the answer .
use parallel axis theorem
Answered by afrinfathima38
6

Explanation:

according to circular disc of mass M and radius R the disc in the tangent perpendicular to the plane of the disc is given by 3 by 2 m r square parallel axis theorem

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