Physics, asked by sukanya05, 1 year ago

The moment of inertia of a uniform cylinder of length l and radius R about its perpendicular bisector is I . What is the ratio L/R such that the moment of inertia is minimum .


sukanya05: I just want to know how will you write the moment of inertia for that .

Answers

Answered by dilkashahbab1
3
Moment of inertia is minimum I=ml2/12+mR2/4=root 3 by 2 is ans
Similar questions