The moment of inertia of an uniform circular disc about its central axis is i. Its moment of inertia about a tangent in its plane isequal to
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Moment of inertia of disc at tangent=5/4mr²=I +mr² (by parallel axis theorem)
I=5/4mr²-mr²=1/4mr²
by perpendicular axis theorem
I+I=I°(perpendicular to plane)
1/4mr²+1/4mr²=mr²/2.
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Hope its help uh...
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
___Sumit tiwari from Azamgarh [UP] (^_-)
Ur answer is here.......
%%%%%%%%%%
ANSWER %%%%
%%%%%%%%%%
Moment of inertia of disc at tangent=5/4mr²=I +mr² (by parallel axis theorem)
I=5/4mr²-mr²=1/4mr²
by perpendicular axis theorem
I+I=I°(perpendicular to plane)
1/4mr²+1/4mr²=mr²/2.
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Hope its help uh...
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
___Sumit tiwari from Azamgarh [UP] (^_-)
Answered by
1
moment of inertia of disc at tangent=5/4mr²=I +mr² (by parallel axis theorem)
I=5/4mr²-mr²=1/4mr²
by perpendicular axis theorem
I+I=I°(perpendicular to plane)
1/4mr²+1/4mr²=mr²/2
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