Physics, asked by shreyashi7551, 1 year ago

The moment of inertia of an uniform circular disc about its central axis is i. Its moment of inertia about a tangent in its plane isequal to

Answers

Answered by nosumittiwari3
2
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Ur answer is here.......


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Moment of inertia of disc at tangent=5/4mr²=I +mr² (by parallel axis theorem)
I=5/4mr²-mr²=1/4mr²
by perpendicular axis theorem
I+I=I°(perpendicular to plane)
1/4mr²+1/4mr²=mr²/2.




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Answered by Anonymous
1

moment of inertia of disc at tangent=5/4mr²=I +mr² (by parallel axis theorem)

I=5/4mr²-mr²=1/4mr²

by perpendicular axis theorem

I+I=I°(perpendicular to plane)

1/4mr²+1/4mr²=mr²/2

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